［文字サイズの変更］
▼
▲
©2024 数学クラブ http://sugaku.club/
月 日（ ）
● 次の等式を[ ]内の変数について解きなさい．
[182-00]
(1)
[
c
]
a
=
4
(
10
b
＋
c
)
＋
5
(2)
v
＋
w
[
v
]
u
=
6
(3)
b
＋
c
[
c
]
a
=
8
(4)
[
q
]
p
=
7
(
q
＋
r
)
(5)
3
(
v
＋
w
)
[
w
]
A
=
u
(6)
8
(
a
＋
b
＋
c
)
[
b
]
X
=
7
(7)
9
(
a
＋
b
＋
c
)
[
a
]
X
=
2
(8)
(
b
＋
c
)
h
[
c
]
a
=
3
(9)
[
q
]
m
=
8
(
p
＋
q
＋
r
)
(10)
y
＋
z
[
y
]
x
=
2
©2024 数学クラブ http://sugaku.club/
月 日（ ）
【解答例】
(1)
[
c
]
a
=
4
(
10
b
＋
c
)
＋
5
4
(
10
b
＋
c
)
=
a
−
5
10
b
＋
c
a
−
5
=
4
c
1
5
=
a
−
10
b
−
4
4
(2)
v
＋
w
[
v
]
u
=
6
v
＋
w
6
=
u
v
＋
w
=
6
u
v
=
6
u
−
w
(3)
b
＋
c
[
c
]
a
=
8
b
＋
c
8
=
a
b
＋
c
=
8
a
c
=
8
a
−
b
(4)
[
q
]
p
=
7
(
q
＋
r
)
7
(
q
＋
r
)
=
p
q
＋
r
1
=
p
7
q
1
=
p
−
r
7
(5)
3
(
v
＋
w
)
[
w
]
A
=
u
3
(
v
＋
w
)
u
=
A
v
＋
w
u
A
=
3
w
u
A
=
−
v
3
(6)
8
(
a
＋
b
＋
c
)
[
b
]
X
=
7
8
(
a
＋
b
＋
c
)
7
=
X
a
＋
b
＋
c
7
=
X
8
b
7
=
X
−
a
−
c
8
(7)
9
(
a
＋
b
＋
c
)
[
a
]
X
=
2
9
(
a
＋
b
＋
c
)
2
=
X
a
＋
b
＋
c
2
=
X
9
a
2
=
X
−
b
−
c
9
(8)
(
b
＋
c
)
h
[
c
]
a
=
3
(
b
＋
c
)
h
3
=
a
b
＋
c
3
a
=
h
c
3
a
=
−
b
h
(9)
[
q
]
m
=
8
(
p
＋
q
＋
r
)
8
(
p
＋
q
＋
r
)
=
m
p
＋
q
＋
r
1
=
m
8
q
1
=
m
−
p
−
r
8
(10)
y
＋
z
[
y
]
x
=
2
y
＋
z
2
=
x
y
＋
z
=
2
x
y
=
2
x
−
z