［文字サイズの変更］
▼
▲
©2026 数学クラブ http://sugaku.club/
月 日（ ）
● 次の等式を[ ]内の変数について解きなさい．
[182-00]
(1)
6
(
x
＋
y
＋
z
)
[
x
]
S
=
2
(2)
[
q
]
p
=
3
(
q
＋
r
)
(3)
2
(
p
＋
q
＋
r
)
[
q
]
m
=
3
(4)
[
b
]
a
=
10
(
8
b
＋
c
)
＋
9
(5)
[
p
]
m
=
3
(
p
＋
q
＋
r
)
(6)
[
v
]
u
=
4
(
v
＋
w
)
(7)
[
b
]
X
=
3
(
a
＋
b
＋
c
)
(8)
[
r
]
p
=
6
(
6
q
＋
r
)
＋
6
(9)
[
q
]
p
=
8
(
q
＋
r
)
(10)
[
v
]
u
=
8
(
6
v
＋
w
)
＋
1
©2026 数学クラブ http://sugaku.club/
月 日（ ）
【解答例】
(1)
6
(
x
＋
y
＋
z
)
[
x
]
S
=
2
6
(
x
＋
y
＋
z
)
2
=
S
x
＋
y
＋
z
1
=
S
3
x
1
=
S
−
y
−
z
3
(2)
[
q
]
p
=
3
(
q
＋
r
)
3
(
q
＋
r
)
=
p
q
＋
r
1
=
p
3
q
1
=
p
−
r
3
(3)
2
(
p
＋
q
＋
r
)
[
q
]
m
=
3
2
(
p
＋
q
＋
r
)
3
=
m
p
＋
q
＋
r
3
=
m
2
q
3
=
m
−
p
−
r
2
(4)
[
b
]
a
=
10
(
8
b
＋
c
)
＋
9
10
(
8
b
＋
c
)
=
a
−
9
8
b
＋
c
a
−
9
=
10
8
b
1
9
=
a
−
c
−
10
10
b
1
1
9
=
a
−
c
−
80
8
80
(5)
[
p
]
m
=
3
(
p
＋
q
＋
r
)
3
(
p
＋
q
＋
r
)
=
m
p
＋
q
＋
r
1
=
m
3
p
1
=
m
−
q
−
r
3
(6)
[
v
]
u
=
4
(
v
＋
w
)
4
(
v
＋
w
)
=
u
v
＋
w
1
=
u
4
v
1
=
u
−
w
4
(7)
[
b
]
X
=
3
(
a
＋
b
＋
c
)
3
(
a
＋
b
＋
c
)
=
X
a
＋
b
＋
c
1
=
X
3
b
1
=
X
−
a
−
c
3
(8)
[
r
]
p
=
6
(
6
q
＋
r
)
＋
6
6
(
6
q
＋
r
)
=
p
−
6
6
q
＋
r
p
−
6
=
6
r
1
=
p
−
6
q
−
1
6
(9)
[
q
]
p
=
8
(
q
＋
r
)
8
(
q
＋
r
)
=
p
q
＋
r
1
=
p
8
q
1
=
p
−
r
8
(10)
[
v
]
u
=
8
(
6
v
＋
w
)
＋
1
8
(
6
v
＋
w
)
=
u
−
1
6
v
＋
w
u
−
1
=
8
6
v
1
1
=
u
−
w
−
8
8
v
1
1
1
=
u
−
w
−
48
6
48