［文字サイズの変更］
▼
▲
©2026 数学クラブ http://sugaku.club/
月 日（ ）
● 次の等式を[ ]内の変数について解きなさい．
[182-00]
(1)
8
(
v
＋
w
)
[
v
]
A
=
u
(2)
7
(
p
＋
q
＋
r
)
[
p
]
m
=
8
(3)
9
(
a
＋
b
＋
c
)
[
b
]
X
=
5
(4)
10
(
x
＋
y
＋
z
)
[
z
]
S
=
10
(5)
[
w
]
A
=
8
(
u
＋
v
＋
w
)
(6)
2
(
a
＋
b
＋
c
)
[
c
]
X
=
5
(7)
[
y
]
S
=
2
(
x
＋
y
＋
z
)
(8)
8
(
y
＋
z
)
[
y
]
S
=
x
(9)
y
＋
z
[
y
]
x
=
3
(10)
[
q
]
p
=
6
(
3
q
＋
r
)
＋
1
©2026 数学クラブ http://sugaku.club/
月 日（ ）
【解答例】
(1)
8
(
v
＋
w
)
[
v
]
A
=
u
8
(
v
＋
w
)
u
=
A
v
＋
w
u
A
=
8
v
u
A
=
−
w
8
(2)
7
(
p
＋
q
＋
r
)
[
p
]
m
=
8
7
(
p
＋
q
＋
r
)
8
=
m
p
＋
q
＋
r
8
=
m
7
p
8
=
m
−
q
−
r
7
(3)
9
(
a
＋
b
＋
c
)
[
b
]
X
=
5
9
(
a
＋
b
＋
c
)
5
=
X
a
＋
b
＋
c
5
=
X
9
b
5
=
X
−
a
−
c
9
(4)
10
(
x
＋
y
＋
z
)
[
z
]
S
=
10
10
(
x
＋
y
＋
z
)
10
=
S
x
＋
y
＋
z
=
S
z
=
S
−
x
−
y
(5)
[
w
]
A
=
8
(
u
＋
v
＋
w
)
8
(
u
＋
v
＋
w
)
=
A
u
＋
v
＋
w
1
=
A
8
w
1
=
A
−
u
−
v
8
(6)
2
(
a
＋
b
＋
c
)
[
c
]
X
=
5
2
(
a
＋
b
＋
c
)
5
=
X
a
＋
b
＋
c
5
=
X
2
c
5
=
X
−
a
−
b
2
(7)
[
y
]
S
=
2
(
x
＋
y
＋
z
)
2
(
x
＋
y
＋
z
)
=
S
x
＋
y
＋
z
1
=
S
2
y
1
=
S
−
x
−
z
2
(8)
8
(
y
＋
z
)
[
y
]
S
=
x
8
(
y
＋
z
)
x
=
S
y
＋
z
x
S
=
8
y
x
S
=
−
z
8
(9)
y
＋
z
[
y
]
x
=
3
y
＋
z
3
=
x
y
＋
z
=
3
x
y
=
3
x
−
z
(10)
[
q
]
p
=
6
(
3
q
＋
r
)
＋
1
6
(
3
q
＋
r
)
=
p
−
1
3
q
＋
r
p
−
1
=
6
3
q
1
1
=
p
−
r
−
6
6
q
1
1
1
=
p
−
r
−
18
3
18