［文字サイズの変更］
▼
▲
©2018 数学クラブ http://sugaku.club/
月 日（ ）
● 次の等式を[ ]内の変数について解きなさい．
[182-00]
(1)
5
(
a
＋
b
＋
c
)
[
a
]
X
=
5
(2)
4
(
b
＋
c
)
[
c
]
X
=
a
(3)
(
q
＋
r
)
l
[
q
]
p
=
9
(4)
(
q
＋
r
)
l
[
r
]
p
=
6
(5)
[
z
]
x
=
10
(
8
y
＋
z
)
＋
4
(6)
[
a
]
X
=
4
(
a
＋
b
＋
c
)
(7)
(
q
＋
r
)
l
[
q
]
p
=
7
(8)
(
b
＋
c
)
h
[
c
]
a
=
5
(9)
8
(
a
＋
b
＋
c
)
[
c
]
X
=
2
(10)
2
(
x
＋
y
＋
z
)
[
y
]
S
=
5
©2018 数学クラブ http://sugaku.club/
月 日（ ）
【解答例】
(1)
5
(
a
＋
b
＋
c
)
[
a
]
X
=
5
5
(
a
＋
b
＋
c
)
5
=
X
a
＋
b
＋
c
=
X
a
=
X
−
b
−
c
(2)
4
(
b
＋
c
)
[
c
]
X
=
a
4
(
b
＋
c
)
a
=
X
b
＋
c
a
X
=
4
c
a
X
=
−
b
4
(3)
(
q
＋
r
)
l
[
q
]
p
=
9
(
q
＋
r
)
l
9
=
p
q
＋
r
9
p
=
l
q
9
p
=
−
r
l
(4)
(
q
＋
r
)
l
[
r
]
p
=
6
(
q
＋
r
)
l
6
=
p
q
＋
r
6
p
=
l
r
6
p
=
−
q
l
(5)
[
z
]
x
=
10
(
8
y
＋
z
)
＋
4
10
(
8
y
＋
z
)
=
x
−
4
8
y
＋
z
x
−
4
=
10
z
1
2
=
x
−
8
y
−
10
5
(6)
[
a
]
X
=
4
(
a
＋
b
＋
c
)
4
(
a
＋
b
＋
c
)
=
X
a
＋
b
＋
c
1
=
X
4
a
1
=
X
−
b
−
c
4
(7)
(
q
＋
r
)
l
[
q
]
p
=
7
(
q
＋
r
)
l
7
=
p
q
＋
r
7
p
=
l
q
7
p
=
−
r
l
(8)
(
b
＋
c
)
h
[
c
]
a
=
5
(
b
＋
c
)
h
5
=
a
b
＋
c
5
a
=
h
c
5
a
=
−
b
h
(9)
8
(
a
＋
b
＋
c
)
[
c
]
X
=
2
8
(
a
＋
b
＋
c
)
2
=
X
a
＋
b
＋
c
1
=
X
4
c
1
=
X
−
a
−
b
4
(10)
2
(
x
＋
y
＋
z
)
[
y
]
S
=
5
2
(
x
＋
y
＋
z
)
5
=
S
x
＋
y
＋
z
5
=
S
2
y
5
=
S
−
x
−
z
2