［文字サイズの変更］
▼
▲
©2025 数学クラブ http://sugaku.club/
月 日（ ）
● 次の等式を[ ]内の変数について解きなさい．
[182-00]
(1)
[
w
]
u
=
3
(
7
v
＋
w
)
＋
8
(2)
[
c
]
a
=
8
(
b
＋
c
)
(3)
3
(
b
＋
c
)
[
b
]
X
=
a
(4)
[
r
]
p
=
7
(
2
q
＋
r
)
＋
6
(5)
[
c
]
a
=
6
(
b
＋
c
)
(6)
[
z
]
S
=
7
(
x
＋
y
＋
z
)
(7)
b
＋
c
[
c
]
a
=
2
(8)
(
y
＋
z
)
r
[
z
]
x
=
8
(9)
5
(
a
＋
b
＋
c
)
[
a
]
X
=
2
(10)
[
v
]
A
=
8
(
u
＋
v
＋
w
)
©2025 数学クラブ http://sugaku.club/
月 日（ ）
【解答例】
(1)
[
w
]
u
=
3
(
7
v
＋
w
)
＋
8
3
(
7
v
＋
w
)
=
u
−
8
7
v
＋
w
u
−
8
=
3
w
1
8
=
u
−
7
v
−
3
3
(2)
[
c
]
a
=
8
(
b
＋
c
)
8
(
b
＋
c
)
=
a
b
＋
c
1
=
a
8
c
1
=
a
−
b
8
(3)
3
(
b
＋
c
)
[
b
]
X
=
a
3
(
b
＋
c
)
a
=
X
b
＋
c
a
X
=
3
b
a
X
=
−
c
3
(4)
[
r
]
p
=
7
(
2
q
＋
r
)
＋
6
7
(
2
q
＋
r
)
=
p
−
6
2
q
＋
r
p
−
6
=
7
r
1
6
=
p
−
2
q
−
7
7
(5)
[
c
]
a
=
6
(
b
＋
c
)
6
(
b
＋
c
)
=
a
b
＋
c
1
=
a
6
c
1
=
a
−
b
6
(6)
[
z
]
S
=
7
(
x
＋
y
＋
z
)
7
(
x
＋
y
＋
z
)
=
S
x
＋
y
＋
z
1
=
S
7
z
1
=
S
−
x
−
y
7
(7)
b
＋
c
[
c
]
a
=
2
b
＋
c
2
=
a
b
＋
c
=
2
a
c
=
2
a
−
b
(8)
(
y
＋
z
)
r
[
z
]
x
=
8
(
y
＋
z
)
r
8
=
x
y
＋
z
8
x
=
r
z
8
x
=
−
y
r
(9)
5
(
a
＋
b
＋
c
)
[
a
]
X
=
2
5
(
a
＋
b
＋
c
)
2
=
X
a
＋
b
＋
c
2
=
X
5
a
2
=
X
−
b
−
c
5
(10)
[
v
]
A
=
8
(
u
＋
v
＋
w
)
8
(
u
＋
v
＋
w
)
=
A
u
＋
v
＋
w
1
=
A
8
v
1
=
A
−
u
−
w
8