［文字サイズの変更］
▼
▲
©2018 数学クラブ http://sugaku.club/
月 日（ ）
● 次の等式を[ ]内の変数について解きなさい．
[182-00]
(1)
2
(
b
＋
c
)
[
c
]
X
=
a
(2)
[
a
]
X
=
5
(
a
＋
b
＋
c
)
(3)
(
y
＋
z
)
r
[
z
]
x
=
7
(4)
(
q
＋
r
)
l
[
q
]
p
=
5
(5)
(
v
＋
w
)
B
[
v
]
u
=
5
(6)
[
v
]
u
=
7
(
v
＋
w
)
(7)
2
(
v
＋
w
)
[
v
]
A
=
u
(8)
5
(
a
＋
b
＋
c
)
[
c
]
X
=
9
(9)
(
q
＋
r
)
l
[
r
]
p
=
3
(10)
[
b
]
a
=
3
(
7
b
＋
c
)
＋
3
©2018 数学クラブ http://sugaku.club/
月 日（ ）
【解答例】
(1)
2
(
b
＋
c
)
[
c
]
X
=
a
2
(
b
＋
c
)
a
=
X
b
＋
c
a
X
=
2
c
a
X
=
−
b
2
(2)
[
a
]
X
=
5
(
a
＋
b
＋
c
)
5
(
a
＋
b
＋
c
)
=
X
a
＋
b
＋
c
1
=
X
5
a
1
=
X
−
b
−
c
5
(3)
(
y
＋
z
)
r
[
z
]
x
=
7
(
y
＋
z
)
r
7
=
x
y
＋
z
7
x
=
r
z
7
x
=
−
y
r
(4)
(
q
＋
r
)
l
[
q
]
p
=
5
(
q
＋
r
)
l
5
=
p
q
＋
r
5
p
=
l
q
5
p
=
−
r
l
(5)
(
v
＋
w
)
B
[
v
]
u
=
5
(
v
＋
w
)
B
5
=
u
v
＋
w
5
u
=
B
v
5
u
=
−
w
B
(6)
[
v
]
u
=
7
(
v
＋
w
)
7
(
v
＋
w
)
=
u
v
＋
w
1
=
u
7
v
1
=
u
−
w
7
(7)
2
(
v
＋
w
)
[
v
]
A
=
u
2
(
v
＋
w
)
u
=
A
v
＋
w
u
A
=
2
v
u
A
=
−
w
2
(8)
5
(
a
＋
b
＋
c
)
[
c
]
X
=
9
5
(
a
＋
b
＋
c
)
9
=
X
a
＋
b
＋
c
9
=
X
5
c
9
=
X
−
a
−
b
5
(9)
(
q
＋
r
)
l
[
r
]
p
=
3
(
q
＋
r
)
l
3
=
p
q
＋
r
3
p
=
l
r
3
p
=
−
q
l
(10)
[
b
]
a
=
3
(
7
b
＋
c
)
＋
3
3
(
7
b
＋
c
)
=
a
−
3
7
b
＋
c
a
−
3
=
3
7
b
1
=
a
−
c
−
1
3
b
1
1
1
=
a
−
c
−
21
7
7