[文字サイズの変更]
▼
▲
©2024 数学クラブ http://sugaku.club/
月 日( )
● 次の等式を[ ]内の変数について解きなさい.
[182-20]
(1)
6
[
b
]
X
=
(
a
+
b
+
c
)
5
(2)
(
b
+
c
)
[
c
]
X
=
2
a
(3)
[
y
]
x
=
2
(
y
+
z
)
(4)
1
2
1
[
r
]
p
=
(
−
q
+
r
)
+
2
5
2
©2024 数学クラブ http://sugaku.club/
月 日( )
【解答例】
(1)
6
[
b
]
X
=
(
a
+
b
+
c
)
5
6
(
a
+
b
+
c
)
5
=
X
a
+
b
+
c
5
=
X
6
b
5
=
X
−
a
−
c
6
(2)
(
b
+
c
)
[
c
]
X
=
2
a
(
b
+
c
)
2
a
=
X
b
+
c
=
2
a
X
c
=
2
a
X
−
b
(3)
[
y
]
x
=
2
(
y
+
z
)
2
(
y
+
z
)
=
x
y
+
z
1
=
x
2
y
1
=
x
−
z
2
(4)
1
2
1
[
r
]
p
=
(
−
q
+
r
)
+
2
5
2
1
2
(
−
q
+
r
)
2
5
1
=
p
−
2
2
−
q
+
r
5
1
=
2
(
p
−
)
2
r
2
=
2
p
+
q
−
1
5