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©2025 数学クラブ http://sugaku.club/
月 日（ ）
● 次の計算をしなさい
[1C1-00]
(1)
2
88
(2)
2
77
(3)
2
52
(4)
2
61
(5)
93
×
87
(6)
102
×
98
(7)
2
27
(8)
41
×
39
(9)
2
87
(10)
2
87
(11)
97
×
103
(12)
2
31
©2025 数学クラブ http://sugaku.club/
月 日（ ）
【解答例】
(1)
2
88
2
2
2
=
(
90
−
2
)
=
90
−
2
×
90
×
2
＋
2
=
8100
−
360
＋
4
=
7744
(2)
2
77
2
2
2
=
(
80
−
3
)
=
80
−
2
×
80
×
3
＋
3
=
6400
−
480
＋
9
=
5929
(3)
2
52
2
2
2
=
(
50
＋
2
)
=
50
＋
2
×
50
×
2
＋
2
=
2500
＋
200
＋
4
=
2704
(4)
2
61
2
2
2
=
(
60
＋
1
)
=
60
＋
2
×
60
×
1
＋
1
=
3600
＋
120
＋
1
=
3721
(5)
93
×
87
2
2
=
(
90
＋
3
)
(
90
−
3
)
=
90
−
3
=
8100
−
9
=
8091
(6)
102
×
98
2
2
=
(
100
＋
2
)
(
100
−
2
)
=
100
−
2
=
10000
−
4
=
9996
(7)
2
27
2
2
2
=
(
30
−
3
)
=
30
−
2
×
30
×
3
＋
3
=
900
−
180
＋
9
=
729
(8)
41
×
39
2
2
=
(
40
＋
1
)
(
40
−
1
)
=
40
−
1
=
1600
−
1
=
1599
(9)
2
87
2
2
2
=
(
90
−
3
)
=
90
−
2
×
90
×
3
＋
3
=
8100
−
540
＋
9
=
7569
(10)
2
87
2
2
2
=
(
90
−
3
)
=
90
−
2
×
90
×
3
＋
3
=
8100
−
540
＋
9
=
7569
(11)
97
×
103
2
2
=
(
100
−
3
)
(
100
＋
3
)
=
100
−
3
=
10000
−
9
=
9991
(12)
2
31
2
2
2
=
(
30
＋
1
)
=
30
＋
2
×
30
×
1
＋
1
=
900
＋
60
＋
1
=
961