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©2026 数学クラブ http://sugaku.club/
月 日（ ）
● 次の計算をしなさい
[1C1-00]
(1)
98
×
102
(2)
2
49
(3)
39
×
41
(4)
2
51
(5)
2
72
(6)
2
88
(7)
99
×
101
(8)
2
48
(9)
2
31
(10)
2
83
(11)
47
×
53
(12)
2
48
©2026 数学クラブ http://sugaku.club/
月 日（ ）
【解答例】
(1)
98
×
102
2
2
=
(
100
−
2
)
(
100
＋
2
)
=
100
−
2
=
10000
−
4
=
9996
(2)
2
49
2
2
2
=
(
50
−
1
)
=
50
−
2
×
50
×
1
＋
1
=
2500
−
100
＋
1
=
2401
(3)
39
×
41
2
2
=
(
40
−
1
)
(
40
＋
1
)
=
40
−
1
=
1600
−
1
=
1599
(4)
2
51
2
2
2
=
(
50
＋
1
)
=
50
＋
2
×
50
×
1
＋
1
=
2500
＋
100
＋
1
=
2601
(5)
2
72
2
2
2
=
(
70
＋
2
)
=
70
＋
2
×
70
×
2
＋
2
=
4900
＋
280
＋
4
=
5184
(6)
2
88
2
2
2
=
(
90
−
2
)
=
90
−
2
×
90
×
2
＋
2
=
8100
−
360
＋
4
=
7744
(7)
99
×
101
2
2
=
(
100
−
1
)
(
100
＋
1
)
=
100
−
1
=
10000
−
1
=
9999
(8)
2
48
2
2
2
=
(
50
−
2
)
=
50
−
2
×
50
×
2
＋
2
=
2500
−
200
＋
4
=
2304
(9)
2
31
2
2
2
=
(
30
＋
1
)
=
30
＋
2
×
30
×
1
＋
1
=
900
＋
60
＋
1
=
961
(10)
2
83
2
2
2
=
(
80
＋
3
)
=
80
＋
2
×
80
×
3
＋
3
=
6400
＋
480
＋
9
=
6889
(11)
47
×
53
2
2
=
(
50
−
3
)
(
50
＋
3
)
=
50
−
3
=
2500
−
9
=
2491
(12)
2
48
2
2
2
=
(
50
−
2
)
=
50
−
2
×
50
×
2
＋
2
=
2500
−
200
＋
4
=
2304