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©2026 数学クラブ http://sugaku.club/
月 日( )
● 次の計算をしなさい
[1C1-00]
(1)
2
29
(2)
2
72
(3)
2
71
(4)
2
22
(5)
2
27
(6)
41
×
39
(7)
2
39
(8)
33
×
27
(9)
2
51
(10)
2
57
(11)
2
82
(12)
2
27
©2026 数学クラブ http://sugaku.club/
月 日( )
【解答例】
(1)
2
29
2
2
2
=
(
30
−
1
)
=
30
−
2
×
30
×
1
+
1
=
900
−
60
+
1
=
841
(2)
2
72
2
2
2
=
(
70
+
2
)
=
70
+
2
×
70
×
2
+
2
=
4900
+
280
+
4
=
5184
(3)
2
71
2
2
2
=
(
70
+
1
)
=
70
+
2
×
70
×
1
+
1
=
4900
+
140
+
1
=
5041
(4)
2
22
2
2
2
=
(
20
+
2
)
=
20
+
2
×
20
×
2
+
2
=
400
+
80
+
4
=
484
(5)
2
27
2
2
2
=
(
30
−
3
)
=
30
−
2
×
30
×
3
+
3
=
900
−
180
+
9
=
729
(6)
41
×
39
2
2
=
(
40
+
1
)
(
40
−
1
)
=
40
−
1
=
1600
−
1
=
1599
(7)
2
39
2
2
2
=
(
40
−
1
)
=
40
−
2
×
40
×
1
+
1
=
1600
−
80
+
1
=
1521
(8)
33
×
27
2
2
=
(
30
+
3
)
(
30
−
3
)
=
30
−
3
=
900
−
9
=
891
(9)
2
51
2
2
2
=
(
50
+
1
)
=
50
+
2
×
50
×
1
+
1
=
2500
+
100
+
1
=
2601
(10)
2
57
2
2
2
=
(
60
−
3
)
=
60
−
2
×
60
×
3
+
3
=
3600
−
360
+
9
=
3249
(11)
2
82
2
2
2
=
(
80
+
2
)
=
80
+
2
×
80
×
2
+
2
=
6400
+
320
+
4
=
6724
(12)
2
27
2
2
2
=
(
30
−
3
)
=
30
−
2
×
30
×
3
+
3
=
900
−
180
+
9
=
729