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©2026 数学クラブ http://sugaku.club/
月 日（ ）
● 次の計算をしなさい
[1C1-00]
(1)
2
51
(2)
43
×
37
(3)
49
×
51
(4)
31
×
29
(5)
103
×
97
(6)
2
79
(7)
2
31
(8)
43
×
37
(9)
68
×
72
(10)
23
×
17
(11)
83
×
77
(12)
2
68
©2026 数学クラブ http://sugaku.club/
月 日（ ）
【解答例】
(1)
2
51
2
2
2
=
(
50
＋
1
)
=
50
＋
2
×
50
×
1
＋
1
=
2500
＋
100
＋
1
=
2601
(2)
43
×
37
2
2
=
(
40
＋
3
)
(
40
−
3
)
=
40
−
3
=
1600
−
9
=
1591
(3)
49
×
51
2
2
=
(
50
−
1
)
(
50
＋
1
)
=
50
−
1
=
2500
−
1
=
2499
(4)
31
×
29
2
2
=
(
30
＋
1
)
(
30
−
1
)
=
30
−
1
=
900
−
1
=
899
(5)
103
×
97
2
2
=
(
100
＋
3
)
(
100
−
3
)
=
100
−
3
=
10000
−
9
=
9991
(6)
2
79
2
2
2
=
(
80
−
1
)
=
80
−
2
×
80
×
1
＋
1
=
6400
−
160
＋
1
=
6241
(7)
2
31
2
2
2
=
(
30
＋
1
)
=
30
＋
2
×
30
×
1
＋
1
=
900
＋
60
＋
1
=
961
(8)
43
×
37
2
2
=
(
40
＋
3
)
(
40
−
3
)
=
40
−
3
=
1600
−
9
=
1591
(9)
68
×
72
2
2
=
(
70
−
2
)
(
70
＋
2
)
=
70
−
2
=
4900
−
4
=
4896
(10)
23
×
17
2
2
=
(
20
＋
3
)
(
20
−
3
)
=
20
−
3
=
400
−
9
=
391
(11)
83
×
77
2
2
=
(
80
＋
3
)
(
80
−
3
)
=
80
−
3
=
6400
−
9
=
6391
(12)
2
68
2
2
2
=
(
70
−
2
)
=
70
−
2
×
70
×
2
＋
2
=
4900
−
280
＋
4
=
4624