[文字サイズの変更]
▼
▲
©2026 数学クラブ http://sugaku.club/
月 日( )
● 次の計算をしなさい
[1C1-00]
(1)
101
×
99
(2)
2
29
(3)
17
×
23
(4)
29
×
31
(5)
2
23
(6)
2
51
(7)
102
×
98
(8)
21
×
19
(9)
59
×
61
(10)
2
61
(11)
2
59
(12)
47
×
53
©2026 数学クラブ http://sugaku.club/
月 日( )
【解答例】
(1)
101
×
99
2
2
=
(
100
+
1
)
(
100
−
1
)
=
100
−
1
=
10000
−
1
=
9999
(2)
2
29
2
2
2
=
(
30
−
1
)
=
30
−
2
×
30
×
1
+
1
=
900
−
60
+
1
=
841
(3)
17
×
23
2
2
=
(
20
−
3
)
(
20
+
3
)
=
20
−
3
=
400
−
9
=
391
(4)
29
×
31
2
2
=
(
30
−
1
)
(
30
+
1
)
=
30
−
1
=
900
−
1
=
899
(5)
2
23
2
2
2
=
(
20
+
3
)
=
20
+
2
×
20
×
3
+
3
=
400
+
120
+
9
=
529
(6)
2
51
2
2
2
=
(
50
+
1
)
=
50
+
2
×
50
×
1
+
1
=
2500
+
100
+
1
=
2601
(7)
102
×
98
2
2
=
(
100
+
2
)
(
100
−
2
)
=
100
−
2
=
10000
−
4
=
9996
(8)
21
×
19
2
2
=
(
20
+
1
)
(
20
−
1
)
=
20
−
1
=
400
−
1
=
399
(9)
59
×
61
2
2
=
(
60
−
1
)
(
60
+
1
)
=
60
−
1
=
3600
−
1
=
3599
(10)
2
61
2
2
2
=
(
60
+
1
)
=
60
+
2
×
60
×
1
+
1
=
3600
+
120
+
1
=
3721
(11)
2
59
2
2
2
=
(
60
−
1
)
=
60
−
2
×
60
×
1
+
1
=
3600
−
120
+
1
=
3481
(12)
47
×
53
2
2
=
(
50
−
3
)
(
50
+
3
)
=
50
−
3
=
2500
−
9
=
2491