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©2026 数学クラブ http://sugaku.club/
月 日( )
● 次の計算をしなさい
[1C1-00]
(1)
2
29
(2)
2
52
(3)
89
×
91
(4)
2
89
(5)
93
×
87
(6)
23
×
17
(7)
39
×
41
(8)
101
×
99
(9)
2
29
(10)
2
47
(11)
2
47
(12)
2
67
©2026 数学クラブ http://sugaku.club/
月 日( )
【解答例】
(1)
2
29
2
2
2
=
(
30
−
1
)
=
30
−
2
×
30
×
1
+
1
=
900
−
60
+
1
=
841
(2)
2
52
2
2
2
=
(
50
+
2
)
=
50
+
2
×
50
×
2
+
2
=
2500
+
200
+
4
=
2704
(3)
89
×
91
2
2
=
(
90
−
1
)
(
90
+
1
)
=
90
−
1
=
8100
−
1
=
8099
(4)
2
89
2
2
2
=
(
90
−
1
)
=
90
−
2
×
90
×
1
+
1
=
8100
−
180
+
1
=
7921
(5)
93
×
87
2
2
=
(
90
+
3
)
(
90
−
3
)
=
90
−
3
=
8100
−
9
=
8091
(6)
23
×
17
2
2
=
(
20
+
3
)
(
20
−
3
)
=
20
−
3
=
400
−
9
=
391
(7)
39
×
41
2
2
=
(
40
−
1
)
(
40
+
1
)
=
40
−
1
=
1600
−
1
=
1599
(8)
101
×
99
2
2
=
(
100
+
1
)
(
100
−
1
)
=
100
−
1
=
10000
−
1
=
9999
(9)
2
29
2
2
2
=
(
30
−
1
)
=
30
−
2
×
30
×
1
+
1
=
900
−
60
+
1
=
841
(10)
2
47
2
2
2
=
(
50
−
3
)
=
50
−
2
×
50
×
3
+
3
=
2500
−
300
+
9
=
2209
(11)
2
47
2
2
2
=
(
50
−
3
)
=
50
−
2
×
50
×
3
+
3
=
2500
−
300
+
9
=
2209
(12)
2
67
2
2
2
=
(
70
−
3
)
=
70
−
2
×
70
×
3
+
3
=
4900
−
420
+
9
=
4489