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©2026 数学クラブ http://sugaku.club/
月 日（ ）
● 次の計算をしなさい
[1C1-00]
(1)
69
×
71
(2)
49
×
51
(3)
2
58
(4)
99
×
101
(5)
67
×
73
(6)
92
×
88
(7)
2
51
(8)
62
×
58
(9)
2
59
(10)
2
49
(11)
22
×
18
(12)
2
53
©2026 数学クラブ http://sugaku.club/
月 日（ ）
【解答例】
(1)
69
×
71
2
2
=
(
70
−
1
)
(
70
＋
1
)
=
70
−
1
=
4900
−
1
=
4899
(2)
49
×
51
2
2
=
(
50
−
1
)
(
50
＋
1
)
=
50
−
1
=
2500
−
1
=
2499
(3)
2
58
2
2
2
=
(
60
−
2
)
=
60
−
2
×
60
×
2
＋
2
=
3600
−
240
＋
4
=
3364
(4)
99
×
101
2
2
=
(
100
−
1
)
(
100
＋
1
)
=
100
−
1
=
10000
−
1
=
9999
(5)
67
×
73
2
2
=
(
70
−
3
)
(
70
＋
3
)
=
70
−
3
=
4900
−
9
=
4891
(6)
92
×
88
2
2
=
(
90
＋
2
)
(
90
−
2
)
=
90
−
2
=
8100
−
4
=
8096
(7)
2
51
2
2
2
=
(
50
＋
1
)
=
50
＋
2
×
50
×
1
＋
1
=
2500
＋
100
＋
1
=
2601
(8)
62
×
58
2
2
=
(
60
＋
2
)
(
60
−
2
)
=
60
−
2
=
3600
−
4
=
3596
(9)
2
59
2
2
2
=
(
60
−
1
)
=
60
−
2
×
60
×
1
＋
1
=
3600
−
120
＋
1
=
3481
(10)
2
49
2
2
2
=
(
50
−
1
)
=
50
−
2
×
50
×
1
＋
1
=
2500
−
100
＋
1
=
2401
(11)
22
×
18
2
2
=
(
20
＋
2
)
(
20
−
2
)
=
20
−
2
=
400
−
4
=
396
(12)
2
53
2
2
2
=
(
50
＋
3
)
=
50
＋
2
×
50
×
3
＋
3
=
2500
＋
300
＋
9
=
2809