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©2026 数学クラブ http://sugaku.club/
月 日（ ）
● 次の計算をしなさい
[1C1-00]
(1)
2
47
(2)
2
68
(3)
2
21
(4)
59
×
61
(5)
2
79
(6)
37
×
43
(7)
93
×
87
(8)
51
×
49
(9)
2
51
(10)
2
39
(11)
2
49
(12)
48
×
52
©2026 数学クラブ http://sugaku.club/
月 日（ ）
【解答例】
(1)
2
47
2
2
2
=
(
50
−
3
)
=
50
−
2
×
50
×
3
＋
3
=
2500
−
300
＋
9
=
2209
(2)
2
68
2
2
2
=
(
70
−
2
)
=
70
−
2
×
70
×
2
＋
2
=
4900
−
280
＋
4
=
4624
(3)
2
21
2
2
2
=
(
20
＋
1
)
=
20
＋
2
×
20
×
1
＋
1
=
400
＋
40
＋
1
=
441
(4)
59
×
61
2
2
=
(
60
−
1
)
(
60
＋
1
)
=
60
−
1
=
3600
−
1
=
3599
(5)
2
79
2
2
2
=
(
80
−
1
)
=
80
−
2
×
80
×
1
＋
1
=
6400
−
160
＋
1
=
6241
(6)
37
×
43
2
2
=
(
40
−
3
)
(
40
＋
3
)
=
40
−
3
=
1600
−
9
=
1591
(7)
93
×
87
2
2
=
(
90
＋
3
)
(
90
−
3
)
=
90
−
3
=
8100
−
9
=
8091
(8)
51
×
49
2
2
=
(
50
＋
1
)
(
50
−
1
)
=
50
−
1
=
2500
−
1
=
2499
(9)
2
51
2
2
2
=
(
50
＋
1
)
=
50
＋
2
×
50
×
1
＋
1
=
2500
＋
100
＋
1
=
2601
(10)
2
39
2
2
2
=
(
40
−
1
)
=
40
−
2
×
40
×
1
＋
1
=
1600
−
80
＋
1
=
1521
(11)
2
49
2
2
2
=
(
50
−
1
)
=
50
−
2
×
50
×
1
＋
1
=
2500
−
100
＋
1
=
2401
(12)
48
×
52
2
2
=
(
50
−
2
)
(
50
＋
2
)
=
50
−
2
=
2500
−
4
=
2496