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©2026 数学クラブ http://sugaku.club/
月 日（ ）
● 次の計算をしなさい
[1C1-00]
(1)
2
49
(2)
2
59
(3)
52
×
48
(4)
37
×
43
(5)
2
79
(6)
32
×
28
(7)
2
78
(8)
53
×
47
(9)
2
32
(10)
2
41
(11)
79
×
81
(12)
59
×
61
©2026 数学クラブ http://sugaku.club/
月 日（ ）
【解答例】
(1)
2
49
2
2
2
=
(
50
−
1
)
=
50
−
2
×
50
×
1
＋
1
=
2500
−
100
＋
1
=
2401
(2)
2
59
2
2
2
=
(
60
−
1
)
=
60
−
2
×
60
×
1
＋
1
=
3600
−
120
＋
1
=
3481
(3)
52
×
48
2
2
=
(
50
＋
2
)
(
50
−
2
)
=
50
−
2
=
2500
−
4
=
2496
(4)
37
×
43
2
2
=
(
40
−
3
)
(
40
＋
3
)
=
40
−
3
=
1600
−
9
=
1591
(5)
2
79
2
2
2
=
(
80
−
1
)
=
80
−
2
×
80
×
1
＋
1
=
6400
−
160
＋
1
=
6241
(6)
32
×
28
2
2
=
(
30
＋
2
)
(
30
−
2
)
=
30
−
2
=
900
−
4
=
896
(7)
2
78
2
2
2
=
(
80
−
2
)
=
80
−
2
×
80
×
2
＋
2
=
6400
−
320
＋
4
=
6084
(8)
53
×
47
2
2
=
(
50
＋
3
)
(
50
−
3
)
=
50
−
3
=
2500
−
9
=
2491
(9)
2
32
2
2
2
=
(
30
＋
2
)
=
30
＋
2
×
30
×
2
＋
2
=
900
＋
120
＋
4
=
1024
(10)
2
41
2
2
2
=
(
40
＋
1
)
=
40
＋
2
×
40
×
1
＋
1
=
1600
＋
80
＋
1
=
1681
(11)
79
×
81
2
2
=
(
80
−
1
)
(
80
＋
1
)
=
80
−
1
=
6400
−
1
=
6399
(12)
59
×
61
2
2
=
(
60
−
1
)
(
60
＋
1
)
=
60
−
1
=
3600
−
1
=
3599