[文字サイズの変更]
▼
▲
©2026 数学クラブ http://sugaku.club/
月 日( )
● 次の計算をしなさい
[1C1-00]
(1)
2
42
(2)
2
29
(3)
2
89
(4)
93
×
87
(5)
49
×
51
(6)
2
89
(7)
99
×
101
(8)
2
23
(9)
22
×
18
(10)
2
33
(11)
18
×
22
(12)
42
×
38
©2026 数学クラブ http://sugaku.club/
月 日( )
【解答例】
(1)
2
42
2
2
2
=
(
40
+
2
)
=
40
+
2
×
40
×
2
+
2
=
1600
+
160
+
4
=
1764
(2)
2
29
2
2
2
=
(
30
−
1
)
=
30
−
2
×
30
×
1
+
1
=
900
−
60
+
1
=
841
(3)
2
89
2
2
2
=
(
90
−
1
)
=
90
−
2
×
90
×
1
+
1
=
8100
−
180
+
1
=
7921
(4)
93
×
87
2
2
=
(
90
+
3
)
(
90
−
3
)
=
90
−
3
=
8100
−
9
=
8091
(5)
49
×
51
2
2
=
(
50
−
1
)
(
50
+
1
)
=
50
−
1
=
2500
−
1
=
2499
(6)
2
89
2
2
2
=
(
90
−
1
)
=
90
−
2
×
90
×
1
+
1
=
8100
−
180
+
1
=
7921
(7)
99
×
101
2
2
=
(
100
−
1
)
(
100
+
1
)
=
100
−
1
=
10000
−
1
=
9999
(8)
2
23
2
2
2
=
(
20
+
3
)
=
20
+
2
×
20
×
3
+
3
=
400
+
120
+
9
=
529
(9)
22
×
18
2
2
=
(
20
+
2
)
(
20
−
2
)
=
20
−
2
=
400
−
4
=
396
(10)
2
33
2
2
2
=
(
30
+
3
)
=
30
+
2
×
30
×
3
+
3
=
900
+
180
+
9
=
1089
(11)
18
×
22
2
2
=
(
20
−
2
)
(
20
+
2
)
=
20
−
2
=
400
−
4
=
396
(12)
42
×
38
2
2
=
(
40
+
2
)
(
40
−
2
)
=
40
−
2
=
1600
−
4
=
1596