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©2026 数学クラブ http://sugaku.club/
月 日( )
● 次の計算をしなさい
[1C1-00]
(1)
2
53
(2)
2
23
(3)
22
×
18
(4)
2
51
(5)
41
×
39
(6)
2
68
(7)
2
87
(8)
82
×
78
(9)
59
×
61
(10)
2
58
(11)
2
67
(12)
2
57
©2026 数学クラブ http://sugaku.club/
月 日( )
【解答例】
(1)
2
53
2
2
2
=
(
50
+
3
)
=
50
+
2
×
50
×
3
+
3
=
2500
+
300
+
9
=
2809
(2)
2
23
2
2
2
=
(
20
+
3
)
=
20
+
2
×
20
×
3
+
3
=
400
+
120
+
9
=
529
(3)
22
×
18
2
2
=
(
20
+
2
)
(
20
−
2
)
=
20
−
2
=
400
−
4
=
396
(4)
2
51
2
2
2
=
(
50
+
1
)
=
50
+
2
×
50
×
1
+
1
=
2500
+
100
+
1
=
2601
(5)
41
×
39
2
2
=
(
40
+
1
)
(
40
−
1
)
=
40
−
1
=
1600
−
1
=
1599
(6)
2
68
2
2
2
=
(
70
−
2
)
=
70
−
2
×
70
×
2
+
2
=
4900
−
280
+
4
=
4624
(7)
2
87
2
2
2
=
(
90
−
3
)
=
90
−
2
×
90
×
3
+
3
=
8100
−
540
+
9
=
7569
(8)
82
×
78
2
2
=
(
80
+
2
)
(
80
−
2
)
=
80
−
2
=
6400
−
4
=
6396
(9)
59
×
61
2
2
=
(
60
−
1
)
(
60
+
1
)
=
60
−
1
=
3600
−
1
=
3599
(10)
2
58
2
2
2
=
(
60
−
2
)
=
60
−
2
×
60
×
2
+
2
=
3600
−
240
+
4
=
3364
(11)
2
67
2
2
2
=
(
70
−
3
)
=
70
−
2
×
70
×
3
+
3
=
4900
−
420
+
9
=
4489
(12)
2
57
2
2
2
=
(
60
−
3
)
=
60
−
2
×
60
×
3
+
3
=
3600
−
360
+
9
=
3249