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©2026 数学クラブ http://sugaku.club/
月 日( )
● 次の計算をしなさい
[1C1-00]
(1)
2
77
(2)
2
49
(3)
91
×
89
(4)
2
62
(5)
97
×
103
(6)
2
81
(7)
2
33
(8)
2
83
(9)
2
89
(10)
49
×
51
(11)
2
82
(12)
2
73
©2026 数学クラブ http://sugaku.club/
月 日( )
【解答例】
(1)
2
77
2
2
2
=
(
80
−
3
)
=
80
−
2
×
80
×
3
+
3
=
6400
−
480
+
9
=
5929
(2)
2
49
2
2
2
=
(
50
−
1
)
=
50
−
2
×
50
×
1
+
1
=
2500
−
100
+
1
=
2401
(3)
91
×
89
2
2
=
(
90
+
1
)
(
90
−
1
)
=
90
−
1
=
8100
−
1
=
8099
(4)
2
62
2
2
2
=
(
60
+
2
)
=
60
+
2
×
60
×
2
+
2
=
3600
+
240
+
4
=
3844
(5)
97
×
103
2
2
=
(
100
−
3
)
(
100
+
3
)
=
100
−
3
=
10000
−
9
=
9991
(6)
2
81
2
2
2
=
(
80
+
1
)
=
80
+
2
×
80
×
1
+
1
=
6400
+
160
+
1
=
6561
(7)
2
33
2
2
2
=
(
30
+
3
)
=
30
+
2
×
30
×
3
+
3
=
900
+
180
+
9
=
1089
(8)
2
83
2
2
2
=
(
80
+
3
)
=
80
+
2
×
80
×
3
+
3
=
6400
+
480
+
9
=
6889
(9)
2
89
2
2
2
=
(
90
−
1
)
=
90
−
2
×
90
×
1
+
1
=
8100
−
180
+
1
=
7921
(10)
49
×
51
2
2
=
(
50
−
1
)
(
50
+
1
)
=
50
−
1
=
2500
−
1
=
2499
(11)
2
82
2
2
2
=
(
80
+
2
)
=
80
+
2
×
80
×
2
+
2
=
6400
+
320
+
4
=
6724
(12)
2
73
2
2
2
=
(
70
+
3
)
=
70
+
2
×
70
×
3
+
3
=
4900
+
420
+
9
=
5329