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©2026 数学クラブ http://sugaku.club/
月 日( )
● 次の計算をしなさい
[1C1-00]
(1)
2
31
(2)
2
52
(3)
88
×
92
(4)
101
×
99
(5)
2
53
(6)
2
83
(7)
2
22
(8)
77
×
83
(9)
39
×
41
(10)
2
47
(11)
2
71
(12)
2
38
©2026 数学クラブ http://sugaku.club/
月 日( )
【解答例】
(1)
2
31
2
2
2
=
(
30
+
1
)
=
30
+
2
×
30
×
1
+
1
=
900
+
60
+
1
=
961
(2)
2
52
2
2
2
=
(
50
+
2
)
=
50
+
2
×
50
×
2
+
2
=
2500
+
200
+
4
=
2704
(3)
88
×
92
2
2
=
(
90
−
2
)
(
90
+
2
)
=
90
−
2
=
8100
−
4
=
8096
(4)
101
×
99
2
2
=
(
100
+
1
)
(
100
−
1
)
=
100
−
1
=
10000
−
1
=
9999
(5)
2
53
2
2
2
=
(
50
+
3
)
=
50
+
2
×
50
×
3
+
3
=
2500
+
300
+
9
=
2809
(6)
2
83
2
2
2
=
(
80
+
3
)
=
80
+
2
×
80
×
3
+
3
=
6400
+
480
+
9
=
6889
(7)
2
22
2
2
2
=
(
20
+
2
)
=
20
+
2
×
20
×
2
+
2
=
400
+
80
+
4
=
484
(8)
77
×
83
2
2
=
(
80
−
3
)
(
80
+
3
)
=
80
−
3
=
6400
−
9
=
6391
(9)
39
×
41
2
2
=
(
40
−
1
)
(
40
+
1
)
=
40
−
1
=
1600
−
1
=
1599
(10)
2
47
2
2
2
=
(
50
−
3
)
=
50
−
2
×
50
×
3
+
3
=
2500
−
300
+
9
=
2209
(11)
2
71
2
2
2
=
(
70
+
1
)
=
70
+
2
×
70
×
1
+
1
=
4900
+
140
+
1
=
5041
(12)
2
38
2
2
2
=
(
40
−
2
)
=
40
−
2
×
40
×
2
+
2
=
1600
−
160
+
4
=
1444