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©2026 数学クラブ http://sugaku.club/
月 日( )
● 次の計算をしなさい
[1C1-00]
(1)
2
38
(2)
51
×
49
(3)
2
47
(4)
87
×
93
(5)
2
23
(6)
2
29
(7)
2
62
(8)
97
×
103
(9)
2
28
(10)
2
61
(11)
2
49
(12)
31
×
29
©2026 数学クラブ http://sugaku.club/
月 日( )
【解答例】
(1)
2
38
2
2
2
=
(
40
−
2
)
=
40
−
2
×
40
×
2
+
2
=
1600
−
160
+
4
=
1444
(2)
51
×
49
2
2
=
(
50
+
1
)
(
50
−
1
)
=
50
−
1
=
2500
−
1
=
2499
(3)
2
47
2
2
2
=
(
50
−
3
)
=
50
−
2
×
50
×
3
+
3
=
2500
−
300
+
9
=
2209
(4)
87
×
93
2
2
=
(
90
−
3
)
(
90
+
3
)
=
90
−
3
=
8100
−
9
=
8091
(5)
2
23
2
2
2
=
(
20
+
3
)
=
20
+
2
×
20
×
3
+
3
=
400
+
120
+
9
=
529
(6)
2
29
2
2
2
=
(
30
−
1
)
=
30
−
2
×
30
×
1
+
1
=
900
−
60
+
1
=
841
(7)
2
62
2
2
2
=
(
60
+
2
)
=
60
+
2
×
60
×
2
+
2
=
3600
+
240
+
4
=
3844
(8)
97
×
103
2
2
=
(
100
−
3
)
(
100
+
3
)
=
100
−
3
=
10000
−
9
=
9991
(9)
2
28
2
2
2
=
(
30
−
2
)
=
30
−
2
×
30
×
2
+
2
=
900
−
120
+
4
=
784
(10)
2
61
2
2
2
=
(
60
+
1
)
=
60
+
2
×
60
×
1
+
1
=
3600
+
120
+
1
=
3721
(11)
2
49
2
2
2
=
(
50
−
1
)
=
50
−
2
×
50
×
1
+
1
=
2500
−
100
+
1
=
2401
(12)
31
×
29
2
2
=
(
30
+
1
)
(
30
−
1
)
=
30
−
1
=
900
−
1
=
899