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©2026 数学クラブ http://sugaku.club/
月 日( )
● 次の計算をしなさい
[1C1-00]
(1)
2
49
(2)
2
49
(3)
2
78
(4)
2
78
(5)
22
×
18
(6)
2
28
(7)
2
88
(8)
93
×
87
(9)
2
88
(10)
101
×
99
(11)
33
×
27
(12)
2
48
©2026 数学クラブ http://sugaku.club/
月 日( )
【解答例】
(1)
2
49
2
2
2
=
(
50
−
1
)
=
50
−
2
×
50
×
1
+
1
=
2500
−
100
+
1
=
2401
(2)
2
49
2
2
2
=
(
50
−
1
)
=
50
−
2
×
50
×
1
+
1
=
2500
−
100
+
1
=
2401
(3)
2
78
2
2
2
=
(
80
−
2
)
=
80
−
2
×
80
×
2
+
2
=
6400
−
320
+
4
=
6084
(4)
2
78
2
2
2
=
(
80
−
2
)
=
80
−
2
×
80
×
2
+
2
=
6400
−
320
+
4
=
6084
(5)
22
×
18
2
2
=
(
20
+
2
)
(
20
−
2
)
=
20
−
2
=
400
−
4
=
396
(6)
2
28
2
2
2
=
(
30
−
2
)
=
30
−
2
×
30
×
2
+
2
=
900
−
120
+
4
=
784
(7)
2
88
2
2
2
=
(
90
−
2
)
=
90
−
2
×
90
×
2
+
2
=
8100
−
360
+
4
=
7744
(8)
93
×
87
2
2
=
(
90
+
3
)
(
90
−
3
)
=
90
−
3
=
8100
−
9
=
8091
(9)
2
88
2
2
2
=
(
90
−
2
)
=
90
−
2
×
90
×
2
+
2
=
8100
−
360
+
4
=
7744
(10)
101
×
99
2
2
=
(
100
+
1
)
(
100
−
1
)
=
100
−
1
=
10000
−
1
=
9999
(11)
33
×
27
2
2
=
(
30
+
3
)
(
30
−
3
)
=
30
−
3
=
900
−
9
=
891
(12)
2
48
2
2
2
=
(
50
−
2
)
=
50
−
2
×
50
×
2
+
2
=
2500
−
200
+
4
=
2304