[文字サイズの変更]
▼
▲
©2026 数学クラブ http://sugaku.club/
月 日( )
● 次の計算をしなさい
[1C1-00]
(1)
2
89
(2)
2
53
(3)
2
69
(4)
2
32
(5)
2
59
(6)
2
28
(7)
101
×
99
(8)
2
22
(9)
2
42
(10)
2
29
(11)
67
×
73
(12)
2
33
©2026 数学クラブ http://sugaku.club/
月 日( )
【解答例】
(1)
2
89
2
2
2
=
(
90
−
1
)
=
90
−
2
×
90
×
1
+
1
=
8100
−
180
+
1
=
7921
(2)
2
53
2
2
2
=
(
50
+
3
)
=
50
+
2
×
50
×
3
+
3
=
2500
+
300
+
9
=
2809
(3)
2
69
2
2
2
=
(
70
−
1
)
=
70
−
2
×
70
×
1
+
1
=
4900
−
140
+
1
=
4761
(4)
2
32
2
2
2
=
(
30
+
2
)
=
30
+
2
×
30
×
2
+
2
=
900
+
120
+
4
=
1024
(5)
2
59
2
2
2
=
(
60
−
1
)
=
60
−
2
×
60
×
1
+
1
=
3600
−
120
+
1
=
3481
(6)
2
28
2
2
2
=
(
30
−
2
)
=
30
−
2
×
30
×
2
+
2
=
900
−
120
+
4
=
784
(7)
101
×
99
2
2
=
(
100
+
1
)
(
100
−
1
)
=
100
−
1
=
10000
−
1
=
9999
(8)
2
22
2
2
2
=
(
20
+
2
)
=
20
+
2
×
20
×
2
+
2
=
400
+
80
+
4
=
484
(9)
2
42
2
2
2
=
(
40
+
2
)
=
40
+
2
×
40
×
2
+
2
=
1600
+
160
+
4
=
1764
(10)
2
29
2
2
2
=
(
30
−
1
)
=
30
−
2
×
30
×
1
+
1
=
900
−
60
+
1
=
841
(11)
67
×
73
2
2
=
(
70
−
3
)
(
70
+
3
)
=
70
−
3
=
4900
−
9
=
4891
(12)
2
33
2
2
2
=
(
30
+
3
)
=
30
+
2
×
30
×
3
+
3
=
900
+
180
+
9
=
1089