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©2025 数学クラブ http://sugaku.club/
月 日( )
● 次の計算をしなさい
[1C1-00]
(1)
2
51
(2)
2
59
(3)
2
52
(4)
2
83
(5)
2
38
(6)
2
32
(7)
2
68
(8)
2
73
(9)
93
×
87
(10)
28
×
32
(11)
92
×
88
(12)
2
22
©2025 数学クラブ http://sugaku.club/
月 日( )
【解答例】
(1)
2
51
2
2
2
=
(
50
+
1
)
=
50
+
2
×
50
×
1
+
1
=
2500
+
100
+
1
=
2601
(2)
2
59
2
2
2
=
(
60
−
1
)
=
60
−
2
×
60
×
1
+
1
=
3600
−
120
+
1
=
3481
(3)
2
52
2
2
2
=
(
50
+
2
)
=
50
+
2
×
50
×
2
+
2
=
2500
+
200
+
4
=
2704
(4)
2
83
2
2
2
=
(
80
+
3
)
=
80
+
2
×
80
×
3
+
3
=
6400
+
480
+
9
=
6889
(5)
2
38
2
2
2
=
(
40
−
2
)
=
40
−
2
×
40
×
2
+
2
=
1600
−
160
+
4
=
1444
(6)
2
32
2
2
2
=
(
30
+
2
)
=
30
+
2
×
30
×
2
+
2
=
900
+
120
+
4
=
1024
(7)
2
68
2
2
2
=
(
70
−
2
)
=
70
−
2
×
70
×
2
+
2
=
4900
−
280
+
4
=
4624
(8)
2
73
2
2
2
=
(
70
+
3
)
=
70
+
2
×
70
×
3
+
3
=
4900
+
420
+
9
=
5329
(9)
93
×
87
2
2
=
(
90
+
3
)
(
90
−
3
)
=
90
−
3
=
8100
−
9
=
8091
(10)
28
×
32
2
2
=
(
30
−
2
)
(
30
+
2
)
=
30
−
2
=
900
−
4
=
896
(11)
92
×
88
2
2
=
(
90
+
2
)
(
90
−
2
)
=
90
−
2
=
8100
−
4
=
8096
(12)
2
22
2
2
2
=
(
20
+
2
)
=
20
+
2
×
20
×
2
+
2
=
400
+
80
+
4
=
484