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©2026 数学クラブ http://sugaku.club/
月 日（ ）
● 次の計算をしなさい
[1C1-00]
(1)
2
47
(2)
2
51
(3)
2
89
(4)
57
×
63
(5)
2
22
(6)
57
×
63
(7)
2
61
(8)
57
×
63
(9)
33
×
27
(10)
2
49
(11)
31
×
29
(12)
41
×
39
©2026 数学クラブ http://sugaku.club/
月 日（ ）
【解答例】
(1)
2
47
2
2
2
=
(
50
−
3
)
=
50
−
2
×
50
×
3
＋
3
=
2500
−
300
＋
9
=
2209
(2)
2
51
2
2
2
=
(
50
＋
1
)
=
50
＋
2
×
50
×
1
＋
1
=
2500
＋
100
＋
1
=
2601
(3)
2
89
2
2
2
=
(
90
−
1
)
=
90
−
2
×
90
×
1
＋
1
=
8100
−
180
＋
1
=
7921
(4)
57
×
63
2
2
=
(
60
−
3
)
(
60
＋
3
)
=
60
−
3
=
3600
−
9
=
3591
(5)
2
22
2
2
2
=
(
20
＋
2
)
=
20
＋
2
×
20
×
2
＋
2
=
400
＋
80
＋
4
=
484
(6)
57
×
63
2
2
=
(
60
−
3
)
(
60
＋
3
)
=
60
−
3
=
3600
−
9
=
3591
(7)
2
61
2
2
2
=
(
60
＋
1
)
=
60
＋
2
×
60
×
1
＋
1
=
3600
＋
120
＋
1
=
3721
(8)
57
×
63
2
2
=
(
60
−
3
)
(
60
＋
3
)
=
60
−
3
=
3600
−
9
=
3591
(9)
33
×
27
2
2
=
(
30
＋
3
)
(
30
−
3
)
=
30
−
3
=
900
−
9
=
891
(10)
2
49
2
2
2
=
(
50
−
1
)
=
50
−
2
×
50
×
1
＋
1
=
2500
−
100
＋
1
=
2401
(11)
31
×
29
2
2
=
(
30
＋
1
)
(
30
−
1
)
=
30
−
1
=
900
−
1
=
899
(12)
41
×
39
2
2
=
(
40
＋
1
)
(
40
−
1
)
=
40
−
1
=
1600
−
1
=
1599