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©2026 数学クラブ http://sugaku.club/
月 日( )
● 次の計算をしなさい
[1C1-00]
(1)
2
89
(2)
2
52
(3)
2
79
(4)
2
61
(5)
2
77
(6)
2
57
(7)
71
×
69
(8)
2
63
(9)
47
×
53
(10)
29
×
31
(11)
2
62
(12)
2
43
©2026 数学クラブ http://sugaku.club/
月 日( )
【解答例】
(1)
2
89
2
2
2
=
(
90
−
1
)
=
90
−
2
×
90
×
1
+
1
=
8100
−
180
+
1
=
7921
(2)
2
52
2
2
2
=
(
50
+
2
)
=
50
+
2
×
50
×
2
+
2
=
2500
+
200
+
4
=
2704
(3)
2
79
2
2
2
=
(
80
−
1
)
=
80
−
2
×
80
×
1
+
1
=
6400
−
160
+
1
=
6241
(4)
2
61
2
2
2
=
(
60
+
1
)
=
60
+
2
×
60
×
1
+
1
=
3600
+
120
+
1
=
3721
(5)
2
77
2
2
2
=
(
80
−
3
)
=
80
−
2
×
80
×
3
+
3
=
6400
−
480
+
9
=
5929
(6)
2
57
2
2
2
=
(
60
−
3
)
=
60
−
2
×
60
×
3
+
3
=
3600
−
360
+
9
=
3249
(7)
71
×
69
2
2
=
(
70
+
1
)
(
70
−
1
)
=
70
−
1
=
4900
−
1
=
4899
(8)
2
63
2
2
2
=
(
60
+
3
)
=
60
+
2
×
60
×
3
+
3
=
3600
+
360
+
9
=
3969
(9)
47
×
53
2
2
=
(
50
−
3
)
(
50
+
3
)
=
50
−
3
=
2500
−
9
=
2491
(10)
29
×
31
2
2
=
(
30
−
1
)
(
30
+
1
)
=
30
−
1
=
900
−
1
=
899
(11)
2
62
2
2
2
=
(
60
+
2
)
=
60
+
2
×
60
×
2
+
2
=
3600
+
240
+
4
=
3844
(12)
2
43
2
2
2
=
(
40
+
3
)
=
40
+
2
×
40
×
3
+
3
=
1600
+
240
+
9
=
1849