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▲
©2018 数学クラブ http://sugaku.club/
月 日（ ）
● 計算しなさい
[1Q3-20]
(1)
12
5
5
7
27
5
(
＋
)
(2)
2
5
8
5
5
7
(
＋
)
(3)
2
7
50
7
2
(
＋
)
3
(4)
2
7
2
5
50
7
(
＋
)
(5)
3
7
12
7
2
(
＋
)
9
(6)
125
7
2
5
7
(
−
＋
)
3
(7)
3
7
75
7
2
7
(
＋
)
(8)
12
5
27
5
2
3
(
＋
)
(9)
75
7
3
7
2
3
(
＋
)
(10)
3
7
27
7
2
(
−
)
3
©2018 数学クラブ http://sugaku.club/
月 日（ ）
【解答例】
(1)
12
5
5
7
27
5
(
＋
)
3
5
5
7
3
5
=
2
(
＋
3
)
3
7
3
=
2
＋
6
×
5
2
21
18
=
＋
7
5
(2)
2
5
8
5
5
7
(
＋
)
2
5
2
5
5
7
=
(
2
＋
)
2
2
7
=
2
×
＋
5
4
14
=
＋
5
7
(3)
2
7
50
7
2
(
＋
)
3
2
7
2
7
2
=
(
5
＋
)
3
2
2
2
7
=
5
×
＋
7
3
10
2
14
=
＋
7
21
(4)
2
7
2
5
50
7
(
＋
)
2
7
2
5
2
7
=
(
＋
5
)
1
35
2
=
2
＋
5
×
7
2
35
10
=
＋
35
7
(5)
3
7
12
7
2
(
＋
)
9
3
7
3
7
2
=
(
2
＋
)
9
3
2
3
7
=
2
×
＋
7
9
6
2
21
=
＋
7
63
(6)
125
7
2
5
7
(
−
＋
)
3
5
7
2
5
7
=
5
(
−
＋
)
3
10
5
7
5
=
−
＋
5
×
3
7
10
35
25
=
−
＋
21
7
(7)
3
7
75
7
2
7
(
＋
)
3
7
3
7
2
7
=
(
5
＋
)
3
1
6
=
5
×
＋
7
7
15
1
6
=
＋
7
7
(8)
12
5
27
5
2
3
(
＋
)
3
5
3
5
2
3
=
2
(
3
＋
)
3
2
5
=
6
×
＋
2
5
18
2
10
=
＋
5
5
(9)
75
7
3
7
2
3
(
＋
)
3
7
3
7
2
3
=
5
(
＋
)
3
2
7
=
5
×
＋
5
7
15
5
14
=
＋
7
7
(10)
3
7
27
7
2
(
−
)
3
3
7
3
7
2
=
(
3
−
)
3
3
2
3
7
=
3
×
−
7
3
9
2
21
=
−
7
21