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©2024 数学クラブ http://sugaku.club/
月 日（ ）
● 計算しなさい
[1Q3-20]
(1)
3
5
2
7
27
5
(
＋
)
(2)
5
7
20
7
(
−
1
)
(3)
3
5
27
5
5
7
(
＋
)
(4)
75
7
3
7
1
(
＋
)
(5)
2
3
8
3
1
(
＋
)
2
(6)
8
7
2
2
7
(
＋
)
5
(7)
27
5
147
5
(
−
1
)
(8)
27
5
4
147
5
(
＋
)
5
(9)
3
5
5
12
5
(
−
＋
)
9
(10)
8
7
2
5
2
7
(
＋
)
©2024 数学クラブ http://sugaku.club/
月 日（ ）
【解答例】
(1)
3
5
2
7
27
5
(
＋
)
3
5
2
7
3
5
=
(
＋
3
)
6
35
3
=
＋
3
×
5
210
9
=
＋
35
5
(2)
5
7
20
7
(
−
1
)
5
7
5
7
=
(
2
−
1
)
5
5
7
=
2
×
−
7
10
1
35
=
−
7
7
(3)
3
5
27
5
5
7
(
＋
)
3
5
3
5
5
7
=
(
3
＋
)
3
3
7
=
3
×
＋
5
9
21
=
＋
5
7
(4)
75
7
3
7
1
(
＋
)
3
7
3
7
=
5
(
＋
1
)
3
3
7
=
5
×
＋
5
7
15
5
21
=
＋
7
7
(5)
2
3
8
3
1
(
＋
)
2
2
3
2
3
1
=
(
2
＋
)
2
2
1
2
3
=
2
×
＋
3
2
4
1
6
=
＋
3
6
(6)
8
7
2
2
7
(
＋
)
5
2
7
2
2
7
=
2
(
＋
)
5
4
2
7
2
=
＋
2
×
5
7
4
14
4
=
＋
35
7
(7)
27
5
147
5
(
−
1
)
3
5
3
5
=
3
(
7
−
1
)
3
3
5
=
21
×
−
3
5
63
3
15
=
−
5
5
(8)
27
5
4
147
5
(
＋
)
5
3
5
4
3
5
=
3
(
＋
7
)
5
12
3
5
3
=
＋
21
×
5
5
12
15
63
=
＋
25
5
(9)
3
5
5
12
5
(
−
＋
)
9
3
5
5
3
5
=
(
−
＋
2
)
9
5
3
5
3
=
−
＋
2
×
9
5
1
15
6
=
−
＋
9
5
(10)
8
7
2
5
2
7
(
＋
)
2
7
2
5
2
7
=
2
(
＋
)
1
35
2
=
2
×
2
＋
2
×
7
4
35
4
=
＋
35
7