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©2025 数学クラブ http://sugaku.club/
月 日（ ）
● 計算しなさい
[1Q3-20]
(1)
5
7
125
7
(
−1
＋
)
(2)
8
5
1
98
5
(
−
＋
)
10
(3)
18
5
2
5
2
3
(
＋
)
(4)
5
7
2
7
45
7
(
＋
)
(5)
8
3
1
50
3
(
−
＋
)
3
(6)
5
7
45
7
3
7
(
＋
)
(7)
2
3
3
50
3
(
−
＋
)
4
(8)
3
5
2
7
147
5
(
＋
)
(9)
2
7
2
7
50
7
(
＋
)
(10)
3
7
1
75
7
(
−
＋
)
2
©2025 数学クラブ http://sugaku.club/
月 日（ ）
【解答例】
(1)
5
7
125
7
(
−1
＋
)
5
7
5
7
=
(
−1
＋
5
)
5
7
5
=
−
＋
5
×
7
1
35
25
=
−
＋
7
7
(2)
8
5
1
98
5
(
−
＋
)
10
2
5
1
2
5
=
2
(
−
＋
7
)
10
1
2
5
2
=
−
＋
14
×
5
5
1
10
28
=
−
＋
25
5
(3)
18
5
2
5
2
3
(
＋
)
2
5
2
5
2
3
=
3
(
＋
)
2
1
15
=
3
×
＋
3
×
2
5
6
2
15
=
＋
5
5
(4)
5
7
2
7
45
7
(
＋
)
5
7
2
7
5
7
=
(
＋
3
)
1
10
5
=
＋
3
×
7
7
1
10
15
=
＋
7
7
(5)
8
3
1
50
3
(
−
＋
)
3
2
3
1
2
3
=
2
(
−
＋
5
)
3
2
2
3
2
=
−
＋
10
×
3
3
2
6
20
=
−
＋
9
3
(6)
5
7
45
7
3
7
(
＋
)
5
7
5
7
3
7
=
(
3
＋
)
5
1
15
=
3
×
＋
7
7
15
1
15
=
＋
7
7
(7)
2
3
3
50
3
(
−
＋
)
4
2
3
3
2
3
=
(
−
＋
5
)
4
3
2
3
2
=
−
＋
5
×
4
3
1
6
10
=
−
＋
4
3
(8)
3
5
2
7
147
5
(
＋
)
3
5
2
7
3
5
=
(
＋
7
)
6
35
3
=
＋
7
×
5
210
21
=
＋
35
5
(9)
2
7
2
7
50
7
(
＋
)
2
7
2
7
2
7
=
(
＋
5
)
2
2
=
＋
5
×
7
7
12
=
7
(10)
3
7
1
75
7
(
−
＋
)
2
3
7
1
3
7
=
(
−
＋
5
)
2
1
3
7
3
=
−
＋
5
×
2
7
1
21
15
=
−
＋
14
7