[文字サイズの変更]
▼
▲
©2026 数学クラブ http://sugaku.club/
月 日( )
● 次の方程式を解きなさい
[211-20]
(1)
2
4
(
x
+
1
)
=
49
(2)
6
2
16
(
x
−
)
−
=
0
7
49
(3)
4
2
(
x
+
)
−
1
=
0
5
(4)
1
2
(
x
−
)
−
1
=
0
3
(5)
3
2
81
(
x
+
)
=
2
49
(6)
2
2
49
(
x
−
)
=
5
36
(7)
1
2
(
x
+
)
=
1
3
(8)
5
2
1
(
x
+
)
−
=
0
4
9
(9)
5
2
(
x
+
)
=
1
4
(10)
1
2
4
(
x
+
)
=
5
7
©2026 数学クラブ http://sugaku.club/
月 日( )
【解答例】
(1)
2
(
x
+
1
)
4
=
49
x
+
1
2
=
±
7
x
2
=
−
1
±
7
x
5
9
=
−
,
−
7
7
(2)
6
2
16
(
x
−
)
−
7
49
=
0
6
x
−
7
4
=
±
7
x
6
4
=
±
7
7
x
10
2
=
,
7
7
(3)
4
2
(
x
+
)
−
1
5
=
0
4
x
+
5
=
±
1
x
4
=
−
±
1
5
x
1
9
=
,
−
5
5
(4)
1
2
(
x
−
)
−
1
3
=
0
1
x
−
3
=
±
1
x
1
=
±
1
3
x
4
2
=
,
−
3
3
(5)
3
2
(
x
+
)
2
81
=
49
3
x
+
2
9
=
±
7
x
3
9
=
−
±
2
7
x
3
39
=
−
,
−
14
14
(6)
2
2
(
x
−
)
5
49
=
36
2
x
−
5
7
=
±
6
x
2
7
=
±
5
6
x
47
23
=
,
−
30
30
(7)
1
2
(
x
+
)
3
=
1
1
x
+
3
=
±
1
x
1
=
−
±
1
3
x
2
4
=
,
−
3
3
(8)
5
2
1
(
x
+
)
−
4
9
=
0
5
x
+
4
1
=
±
3
x
5
1
=
−
±
4
3
x
11
19
=
−
,
−
12
12
(9)
5
2
(
x
+
)
4
=
1
5
x
+
4
=
±
1
x
5
=
−
±
1
4
x
1
9
=
−
,
−
4
4
(10)
1
2
(
x
+
)
5
4
=
7
1
x
+
5
2
7
=
±
7
x
1
2
7
=
−
±
5
7