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©2025 数学クラブ http://sugaku.club/
月 日( )
● 次の方程式を解きなさい
[211-20]
(1)
3
2
1
(
x
+
)
−
=
0
2
4
(2)
2
9
(
x
+
1
)
=
4
(3)
2
2
1
(
x
−
)
−
=
0
3
25
(4)
2
2
(
x
+
)
=
1
3
(5)
2
5
(
x
+
1
)
=
7
(6)
1
2
(
x
+
)
−
1
=
0
4
(7)
2
6
(
x
−
1
)
−
=
0
5
(8)
2
2
9
(
x
+
)
−
=
0
5
7
(9)
2
(
x
+
1
)
−
1
=
0
(10)
1
2
2
(
x
+
)
=
3
5
©2025 数学クラブ http://sugaku.club/
月 日( )
【解答例】
(1)
3
2
1
(
x
+
)
−
2
4
=
0
3
x
+
2
1
=
±
2
x
3
1
=
−
±
2
2
x
=
−1
,
−2
(2)
2
(
x
+
1
)
9
=
4
x
+
1
3
=
±
2
x
3
=
−
1
±
2
x
1
5
=
,
−
2
2
(3)
2
2
1
(
x
−
)
−
3
25
=
0
2
x
−
3
1
=
±
5
x
2
1
=
±
3
5
x
13
7
=
,
15
15
(4)
2
2
(
x
+
)
3
=
1
2
x
+
3
=
±
1
x
2
=
−
±
1
3
x
1
5
=
,
−
3
3
(5)
2
(
x
+
1
)
5
=
7
x
+
1
35
=
±
7
x
35
=
−
1
±
7
(6)
1
2
(
x
+
)
−
1
4
=
0
1
x
+
4
=
±
1
x
1
=
−
±
1
4
x
3
5
=
,
−
4
4
(7)
2
6
(
x
−
1
)
−
5
=
0
x
−
1
30
=
±
5
x
30
=
1
±
5
(8)
2
2
9
(
x
+
)
−
5
7
=
0
2
x
+
5
3
7
=
±
7
x
2
3
7
=
−
±
5
7
(9)
2
(
x
+
1
)
−
1
=
0
x
+
1
=
±
1
x
=
−
1
±
1
x
=
0
,
−2
(10)
1
2
(
x
+
)
3
2
=
5
1
x
+
3
10
=
±
5
x
1
10
=
−
±
3
5