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©2024 数学クラブ http://sugaku.club/
月 日( )
● 次の方程式を解きなさい
[211-20]
(1)
1
2
1
(
x
+
)
−
=
0
6
2
(2)
3
2
4
(
x
−
)
−
=
0
7
9
(3)
2
9
(
x
+
1
)
=
4
(4)
1
2
1
(
x
+
)
=
2
2
(5)
5
2
(
x
−
)
−
1
=
0
6
(6)
1
2
36
(
x
+
)
=
4
25
(7)
6
2
1
(
x
−
)
−
=
0
7
9
(8)
1
2
(
x
+
)
−
1
=
0
4
(9)
4
2
(
x
+
)
=
1
3
(10)
2
1
(
x
+
1
)
=
2
©2024 数学クラブ http://sugaku.club/
月 日( )
【解答例】
(1)
1
2
1
(
x
+
)
−
6
2
=
0
1
x
+
6
2
=
±
2
x
1
2
=
−
±
6
2
(2)
3
2
4
(
x
−
)
−
7
9
=
0
3
x
−
7
2
=
±
3
x
3
2
=
±
7
3
x
23
5
=
,
−
21
21
(3)
2
(
x
+
1
)
9
=
4
x
+
1
3
=
±
2
x
3
=
−
1
±
2
x
1
5
=
,
−
2
2
(4)
1
2
(
x
+
)
2
1
=
2
1
x
+
2
2
=
±
2
x
1
2
=
−
±
2
2
(5)
5
2
(
x
−
)
−
1
6
=
0
5
x
−
6
=
±
1
x
5
=
±
1
6
x
11
1
=
,
−
6
6
(6)
1
2
(
x
+
)
4
36
=
25
1
x
+
4
6
=
±
5
x
1
6
=
−
±
4
5
x
19
29
=
,
−
20
20
(7)
6
2
1
(
x
−
)
−
7
9
=
0
6
x
−
7
1
=
±
3
x
6
1
=
±
7
3
x
25
11
=
,
21
21
(8)
1
2
(
x
+
)
−
1
4
=
0
1
x
+
4
=
±
1
x
1
=
−
±
1
4
x
3
5
=
,
−
4
4
(9)
4
2
(
x
+
)
3
=
1
4
x
+
3
=
±
1
x
4
=
−
±
1
3
x
1
7
=
−
,
−
3
3
(10)
2
(
x
+
1
)
1
=
2
x
+
1
2
=
±
2
x
2
=
−
1
±
2