|
(1) ∠x を求めなさい.
60° A 34° B 29° C x D E |
(2) ∠x を求めなさい.
55° A x B 26° C 123° D E |
|
(3) ∠x を求めなさい.
80° A 25° B 25° C x D E |
(4) ∠x を求めなさい.
x 62° 30° 55° |
|
(1) ∠x を求めなさい.
60° A 34° B 29° C x D E ∠BEC = 60 + 34 = 94 ∠BDCは△DCEの頂点Dにおける外角だから∠BDC = ∠C+∠BEC ∠BDC = 29+94 = 123 |
(2) ∠x を求めなさい.
55° A x B 26° C 123° D E よって,∠CED = ∠BDC − ∠C = 123 − 26 = 97 ∠CEDは△ABEの頂点Eにおける外角だから∠CED = ∠A+∠B ∠CED = ∠A + ∠x = 97 よって,∠x = 42 |
|
(3) ∠x を求めなさい.
80° A 25° B 25° C x D E ∠BEC = 80 + 25 = 105 ∠BDCは△DCEの頂点Dにおける外角だから∠BDC = ∠C+∠BEC ∠BDC = 25+105 = 130 |
(4) ∠x を求めなさい.
x 62° 30° 55° 対頂角 = 180−(∠x+55) = 180−(62+30) ∠x = 37 |