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(1) ∠x を求めなさい.
75° A x B 28° C 129° D E F |
(2) ∠x を求めなさい.
65° A 26° B x C 134° D E F |
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(3) ∠x を求めなさい.
50° A x B 28° C 109° D E |
(4) ∠x を求めなさい.
x 41° 46° 31° |
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(1) ∠x を求めなさい.
75° A x B 28° C 129° D E F ∠CFB = 75 + 28 = 103 ∠BDCは△BDFの頂点Dにおける外角だから∠BDC = ∠B+∠CFB ∠B = ∠x = ∠BDC − ∠CFB = 26 |
(2) ∠x を求めなさい.
65° A 26° B x C 134° D E F よって,∠DFB = ∠BDC − ∠B = 134 − 26 = 108 ∠DFBは△AFCの頂点Fにおける外角だから∠DFB = ∠A+∠C ∠DFB = ∠A + ∠x = 108 よって,∠x = 43 |
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(3) ∠x を求めなさい.
50° A x B 28° C 109° D E よって,∠CED = ∠BDC − ∠C = 109 − 28 = 81 ∠CEDは△ABEの頂点Eにおける外角だから∠CED = ∠A+∠B ∠CED = ∠A + ∠x = 81 よって,∠x = 31 |
(4) ∠x を求めなさい.
x 41° 46° 31° 対頂角 = 180−(∠x+31) = 180−(41+46) ∠x = 56 |