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(1) ∠x を求めなさい.
52° 32° x 39° |
(2) ∠x を求めなさい.
47° 32° x 34° |
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(3) ∠x を求めなさい.
65° A 40° B 31° C x D E F |
(4) ∠x を求めなさい.
x A 29° B 28° C 117° D E F |
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(1) ∠x を求めなさい.
52° 32° x 39° 対頂角 = 180−(∠x+32) = 180−(52+39) ∠x = 59 |
(2) ∠x を求めなさい.
47° 32° x 34° 対頂角 = 180−(∠x+32) = 180−(47+34) ∠x = 49 |
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(3) ∠x を求めなさい.
65° A 40° B 31° C x D E F ∠CFB = 65 + 31 = 96 ∠BDCは△BDFの頂点Dにおける外角だから∠BDC = ∠B+∠CFB ∠BDC = 40+96 = 136 |
(4) ∠x を求めなさい.
x A 29° B 28° C 117° D E F よって,∠DFB = ∠BDC − ∠B = 117 − 29 = 88 ∠DFBは△AFCの頂点Fにおける外角だから∠DFB = ∠A+∠C ∠DFB = ∠x + ∠C = 88 よって,∠x = 60 |