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(1) ∠x を求めなさい.
x 59° 45° 65° |
(2) ∠x を求めなさい.
x 55° 32° 48° |
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(3) ∠x を求めなさい.
60° A x B 26° C 131° D E |
(4) ∠x を求めなさい.
80° A 30° B x C 138° D E F |
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(1) ∠x を求めなさい.
x 59° 45° 65° 対頂角 = 180−(∠x+65) = 180−(59+45) ∠x = 39 |
(2) ∠x を求めなさい.
x 55° 32° 48° 対頂角 = 180−(∠x+48) = 180−(55+32) ∠x = 39 |
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(3) ∠x を求めなさい.
60° A x B 26° C 131° D E よって,∠CED = ∠BDC − ∠C = 131 − 26 = 105 ∠CEDは△ABEの頂点Eにおける外角だから∠CED = ∠A+∠B ∠CED = ∠A + ∠x = 105 よって,∠x = 45 |
(4) ∠x を求めなさい.
80° A 30° B x C 138° D E F よって,∠DFB = ∠BDC − ∠B = 138 − 30 = 108 ∠DFBは△AFCの頂点Fにおける外角だから∠DFB = ∠A+∠C ∠DFB = ∠A + ∠x = 108 よって,∠x = 28 |