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(1) ∠x を求めなさい.
x 47° 39° 29° |
(2) ∠x を求めなさい.
x A 30° B 25° C 135° D E |
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(3) ∠x を求めなさい.
65° A 26° B x C 123° D E |
(4) ∠x を求めなさい.
80° A x B 30° C 139° D E |
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(1) ∠x を求めなさい.
x 47° 39° 29° 対頂角 = 180−(∠x+29) = 180−(47+39) ∠x = 57 |
(2) ∠x を求めなさい.
x A 30° B 25° C 135° D E よって,∠CED = ∠BDC − ∠C = 135 − 25 = 110 ∠CEDは△ABEの頂点Eにおける外角だから∠CED = ∠A+∠B ∠CED = ∠x + ∠B = 110 よって,∠x = 80 |
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(3) ∠x を求めなさい.
65° A 26° B x C 123° D E ∠BEC = 65 + 26 = 91 ∠BDCは△DCEの頂点Dにおける外角だから∠BDC = ∠C+∠BEC ∠C = ∠x = ∠BDC − ∠BEC = 32 |
(4) ∠x を求めなさい.
80° A x B 30° C 139° D E よって,∠CED = ∠BDC − ∠C = 139 − 30 = 109 ∠CEDは△ABEの頂点Eにおける外角だから∠CED = ∠A+∠B ∠CED = ∠A + ∠x = 109 よって,∠x = 29 |