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(1) ∠x を求めなさい.
60° A 35° B 40° C x D E F |
(2) ∠x を求めなさい.
43° 43° x 39° |
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(3) ∠x を求めなさい.
58° 28° x 35° |
(4) ∠x を求めなさい.
x A 25° B 26° C 126° D E F |
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(1) ∠x を求めなさい.
60° A 35° B 40° C x D E F ∠CFB = 60 + 40 = 100 ∠BDCは△BDFの頂点Dにおける外角だから∠BDC = ∠B+∠CFB ∠BDC = 35+100 = 135 |
(2) ∠x を求めなさい.
43° 43° x 39° 対頂角 = 180−(∠x+43) = 180−(43+39) ∠x = 39 |
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(3) ∠x を求めなさい.
58° 28° x 35° 対頂角 = 180−(∠x+28) = 180−(58+35) ∠x = 65 |
(4) ∠x を求めなさい.
x A 25° B 26° C 126° D E F よって,∠DFB = ∠BDC − ∠B = 126 − 25 = 101 ∠DFBは△AFCの頂点Fにおける外角だから∠DFB = ∠A+∠C ∠DFB = ∠x + ∠C = 101 よって,∠x = 75 |