|
(1) ∠x を求めなさい.
55° A 38° B x C 129° D E |
(2) ∠x を求めなさい.
39° 54° x 49° |
|
(3) ∠x を求めなさい.
75° A x B 27° C 135° D E F |
(4) ∠x を求めなさい.
35° x 32° 62° |
|
(1) ∠x を求めなさい.
55° A 38° B x C 129° D E ∠BEC = 55 + 38 = 93 ∠BDCは△DCEの頂点Dにおける外角だから∠BDC = ∠C+∠BEC ∠C = ∠x = ∠BDC − ∠BEC = 36 |
(2) ∠x を求めなさい.
39° 54° x 49° 対頂角 = 180−(∠x+54) = 180−(39+49) ∠x = 34 |
|
(3) ∠x を求めなさい.
75° A x B 27° C 135° D E F ∠CFB = 75 + 27 = 102 ∠BDCは△BDFの頂点Dにおける外角だから∠BDC = ∠B+∠CFB ∠B = ∠x = ∠BDC − ∠CFB = 33 |
(4) ∠x を求めなさい.
35° x 32° 62° 対頂角 = 180−(∠x+32) = 180−(35+62) ∠x = 65 |