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(1) ∠x を求めなさい.
x A 29° B 30° C 134° D E |
(2) ∠x を求めなさい.
55° A 25° B x C 116° D E F |
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(3) ∠x を求めなさい.
50° 45° 53° x |
(4) ∠x を求めなさい.
80° A 29° B 28° C x D E F |
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(1) ∠x を求めなさい.
x A 29° B 30° C 134° D E よって,∠CED = ∠BDC − ∠C = 134 − 30 = 104 ∠CEDは△ABEの頂点Eにおける外角だから∠CED = ∠A+∠B ∠CED = ∠x + ∠B = 104 よって,∠x = 75 |
(2) ∠x を求めなさい.
55° A 25° B x C 116° D E F よって,∠DFB = ∠BDC − ∠B = 116 − 25 = 91 ∠DFBは△AFCの頂点Fにおける外角だから∠DFB = ∠A+∠C ∠DFB = ∠A + ∠x = 91 よって,∠x = 36 |
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(3) ∠x を求めなさい.
50° 45° 53° x 対頂角 = 180−(∠x+50) = 180−(45+53) ∠x = 48 |
(4) ∠x を求めなさい.
80° A 29° B 28° C x D E F ∠CFB = 80 + 28 = 108 ∠BDCは△BDFの頂点Dにおける外角だから∠BDC = ∠B+∠CFB ∠BDC = 29+108 = 137 |