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(1) ∠x を求めなさい.
50° A 51° B 28° C x D E F |
(2) ∠x を求めなさい.
x A 28° B 27° C 135° D E F |
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(3) ∠x を求めなさい.
x 75° 33° 68° |
(4) ∠x を求めなさい.
47° x 28° 53° |
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(1) ∠x を求めなさい.
50° A 51° B 28° C x D E F ∠CFB = 50 + 28 = 78 ∠BDCは△BDFの頂点Dにおける外角だから∠BDC = ∠B+∠CFB ∠BDC = 51+78 = 129 |
(2) ∠x を求めなさい.
x A 28° B 27° C 135° D E F よって,∠DFB = ∠BDC − ∠B = 135 − 28 = 107 ∠DFBは△AFCの頂点Fにおける外角だから∠DFB = ∠A+∠C ∠DFB = ∠x + ∠C = 107 よって,∠x = 80 |
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(3) ∠x を求めなさい.
x 75° 33° 68° 対頂角 = 180−(∠x+68) = 180−(75+33) ∠x = 40 |
(4) ∠x を求めなさい.
47° x 28° 53° 対頂角 = 180−(∠x+28) = 180−(47+53) ∠x = 72 |