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(1) ∠x を求めなさい.
x A 33° B 40° C 138° D E F |
(2) ∠x を求めなさい.
x A 38° B 28° C 121° D E F |
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(3) ∠x を求めなさい.
40° x 55° 50° |
(4) ∠x を求めなさい.
70° A 26° B 35° C x D E |
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(1) ∠x を求めなさい.
x A 33° B 40° C 138° D E F よって,∠DFB = ∠BDC − ∠B = 138 − 33 = 105 ∠DFBは△AFCの頂点Fにおける外角だから∠DFB = ∠A+∠C ∠DFB = ∠x + ∠C = 105 よって,∠x = 65 |
(2) ∠x を求めなさい.
x A 38° B 28° C 121° D E F よって,∠DFB = ∠BDC − ∠B = 121 − 38 = 83 ∠DFBは△AFCの頂点Fにおける外角だから∠DFB = ∠A+∠C ∠DFB = ∠x + ∠C = 83 よって,∠x = 55 |
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(3) ∠x を求めなさい.
40° x 55° 50° 対頂角 = 180−(∠x+55) = 180−(40+50) ∠x = 35 |
(4) ∠x を求めなさい.
70° A 26° B 35° C x D E ∠BEC = 70 + 26 = 96 ∠BDCは△DCEの頂点Dにおける外角だから∠BDC = ∠C+∠BEC ∠BDC = 35+96 = 131 |