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(1) ∠x を求めなさい.
35° 50° x 55° |
(2) ∠x を求めなさい.
x A 30° B 30° C 140° D E |
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(3) ∠x を求めなさい.
80° A 29° B x C 135° D E F |
(4) ∠x を求めなさい.
50° x 53° 38° |
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(1) ∠x を求めなさい.
35° 50° x 55° 対頂角 = 180−(∠x+50) = 180−(35+55) ∠x = 40 |
(2) ∠x を求めなさい.
x A 30° B 30° C 140° D E よって,∠CED = ∠BDC − ∠C = 140 − 30 = 110 ∠CEDは△ABEの頂点Eにおける外角だから∠CED = ∠A+∠B ∠CED = ∠x + ∠B = 110 よって,∠x = 80 |
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(3) ∠x を求めなさい.
80° A 29° B x C 135° D E F よって,∠DFB = ∠BDC − ∠B = 135 − 29 = 106 ∠DFBは△AFCの頂点Fにおける外角だから∠DFB = ∠A+∠C ∠DFB = ∠A + ∠x = 106 よって,∠x = 26 |
(4) ∠x を求めなさい.
50° x 53° 38° 対頂角 = 180−(∠x+53) = 180−(50+38) ∠x = 35 |